1/(x^2+1)

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Solution for 1/(x^2+1) equation:


D( x )

x^2+1 = 0

x^2+1 = 0

x^2+1 = 0

1*x^2 = -1 // : 1

x^2 = -1

x in (-oo:+oo)

1/(x^2+1) = 0

x belongs to the empty set

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